On This Page

Chapter 2 Underlying Concepts

Units in particle physics

Natural units

Original thoughts:

Set $\hbar$ and $c$ to 1, which means all physical concepts are transferred into XX times of GeV, $\hbar$ and c. For example,

\[1\text m = \frac{\frac{1}{1.055\times 10 ^{-34}}\hbar{}\cdot \frac{1}{2.998\times 10^8}c}{\frac{1}{1.602\times 10^{-10}}\text {GeV}} = \frac{1}{0.197\times 10^{-15}}(\text{GeV}/\hbar c)^{-1} \to \frac{1}{0.197\times 10^{-15}}\text{GeV}^{-1} \text{(set $\hbar$, c to 1)}\]
Heaviside-Lorentz Units

To simplify the units of electromagnetic problems (to simplify the units of charge!), we set $\varepsilon_0 = 1$(with $c= 1$, we have $\mu_0=1$), so

\[F= \frac{e^2}{4\pi r^2}\]

Special Relativity

\[\text{(invariable)}s = (p_1+p_2)^2 = (p_3+p_4)^2\]

Figure 2: t-channel (ensemble to “scattering”)

\[\text{(invariable)}t = (p_1-p_3)^2 = (p_2-p_4)^2\]

Figure 3: u-channel (ensemble to “scattering”, appears only when it comes to identical particles)

\[\text{(invariable)}u=(p_1-p_4)^2=(p_2-p_3)^2\]

The property of 3 invariants above: \(s+t+u = m_1^2+m_2^2+m_3^2+m_4^2\) Proof: \(\begin{aligned} \text{LHS} &= (p_1+p_2)^2+(p_1-p_3)^2+(p_1-p_4)^2\\ &=p_1^2+p_2^2+p_3^2+p_4^2+2p_1\cdotp p_2 -2p_1(p_3+p_4)+2p_1^2\\ &=p_1^2+p_2^2+p_3^2+p_4^2+2p_1\cdotp p_2 -2p_1(p_1+p_2)+2p_1^2\\ &=p_1^2+p_2^2+p_3^2+p_4^2\\ &=m_1^2+m_2^2+m_3^2+m_4^2\\ &=\text{RHS} \end{aligned}\) Q.E.D.

Non-realistic Quantum Mechanics